5y^2-22y+21=0

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Solution for 5y^2-22y+21=0 equation:



5y^2-22y+21=0
a = 5; b = -22; c = +21;
Δ = b2-4ac
Δ = -222-4·5·21
Δ = 64
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{64}=8$
$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-8}{2*5}=\frac{14}{10} =1+2/5 $
$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+8}{2*5}=\frac{30}{10} =3 $

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